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 | <?xml version="1.0" encoding="UTF-8"?>   <fps version="1.2" url="https://github.com/zhblue/freeproblemset/">
 <generator name="HUSTOJ" url="https://github.com/zhblue/hustoj/"/>
 <item>
 
 
 <title><![CDATA[方阵填数]]></title>
 
 
 <time_limit unit="s"><![CDATA[1]]></time_limit>
 
 
 <memory_limit unit="mb"><![CDATA[125]]></memory_limit>
 
 
 <description><![CDATA[<p>
 在一个N*N的方阵中,填入1,2,……N*N个数,并要求构成如下的格式:
 </p>
 <p>
 例如:
 </p>
 <p>
 N=5
 </p>
 <p>
 <span style="font-family:SimSun;">13 14 15 16  1</span>
 </p>
 <p>
 <span style="font-family:SimSun;">12 23 24 17  2</span>
 </p>
 <p>
 <span style="font-family:SimSun;">11 22 25 18  3</span>
 </p>
 <p>
 <span style="font-family:SimSun;">10 21 20 19  4</span>
 </p>
 <p>
 <span style="font-family:SimSun;"> 9  8  7  6  5</span>
 </p>
 <p>
 <br />
 </p>
 <p>
 N=6
 </p>
 <p>
 <span style="font-family:SimSun;">16 17 18 19 20  1</span>
 </p>
 <p>
 <span style="font-family:SimSun;">15 30 31 32 21  2</span>
 </p>
 <p>
 <span style="font-family:SimSun;">14 29 36 33 22  3</span>
 </p>
 <p>
 <span style="font-family:SimSun;">13 28 35 34 23  4</span>
 </p>
 <p>
 <span style="font-family:SimSun;">12 27 26 25 24  5</span>
 </p>
 <p>
 <span style="font-family:SimSun;">11 10  9  8  7  6</span>
 </p>]]></description>
 
 
 <input><![CDATA[每个测试文件只包含一组测试数据,每组输入一个N。]]></input>
 
 
 <output><![CDATA[输出构成的方阵。]]></output>
 
 
 <sample_input><![CDATA[5
 ]]></sample_input>
 <sample_output><![CDATA[13 14 15 16 1
 12 23 24 17 2
 11 22 25 18 3
 10 21 20 19 4
 9 8 7 6 5
 ]]></sample_output>
 <test_input><![CDATA[10
 ]]></test_input>
 <test_output><![CDATA[28 29 30 31 32 33 34 35 36 1
 27 58 59 60 61 62 63 64 37 2
 26 57 80 81 82 83 84 65 38 3
 25 56 79 94 95 96 85 66 39 4
 24 55 78 93 100 97 86 67 40 5
 23 54 77 92 99 98 87 68 41 6
 22 53 76 91 90 89 88 69 42 7
 21 52 75 74 73 72 71 70 43 8
 20 51 50 49 48 47 46 45 44 9
 19 18 17 16 15 14 13 12 11 10
 ]]></test_output>
 <test_input><![CDATA[1
 ]]></test_input>
 <test_output><![CDATA[ 1
 ]]></test_output>
 <test_input><![CDATA[3
 ]]></test_input>
 <test_output><![CDATA[ 7  8  1
 6  9  2
 5  4  3
 ]]></test_output>
 
 
 <hint><![CDATA[<p>
 6
 </p>
 <p>
 -------------------------
 </p>
 16 17 18 19 20 1<br />
 15 30 31 32 21 2<br />
 14 29 36 33 22 3<br />
 13 28 35 34 23 4<br />
 12 27 26 25 24 5<br />
 11 10 9 8 7 6<br />]]></hint>
 
 
 <source><![CDATA[NOIP全国联赛普及组 1995年NOIP全国联赛普及组]]></source>
 
 
 <solution language="C"><![CDATA[#include <stdio.h>
 
 int main (void)
 {
 int i, n, k, ix, iy;
 
 scanf("%d", &n);
 int A[n][n];
 
 k = 0;
 for(i = 0; i <= n / 2; i++)
 {
 for(ix = i, iy = n - i - 1; ix < n - i - 1; ix++)
 {
 k++;
 A[ix][iy] = k;
 }
 for(ix = n - i - 1, iy = n - i - 1; iy > i; iy--)
 {
 k++;
 A[ix][iy] = k;
 }
 for(ix = n - i - 1, iy = i; ix > i; ix--)
 {
 k++;
 A[ix][iy] = k;
 }
 for(ix = i, iy = i; iy < n - i - 1; iy++)
 {
 k++;
 A[ix][iy] = k;
 }
 }
 if(n % 2 == 1)    A[n / 2][n / 2] = ++k;
 for(ix = 0; ix < n; ix++)
 {
 for(iy = 0; iy < n; iy++)
 {
 if(iy > 0)    printf(" ");
 if(A[ix][iy] < 10&&(iy == 0||A[ix][iy - 1] < 10))    printf(" ");
 printf("%d", A[ix][iy]);
 }
 printf("\n");
 }
 
 return 0;
 }
 ]]></solution>
 <solution language="C++"><![CDATA[#include <iostream>
 #include <string>
 #include <cstdio>
 using namespace std;
 int n;
 int map[200][200]={0};
 void fill_map(int t,int l,int s)
 {
 for(int i=l+1;i<=s;i++)
 map[i][s]=t++;
 for(int i=s-1;i>=l+1;i--)
 map[s][i]=t++;
 for(int i=s-1;i>=l+1;i--)
 map[i][l+1]=t++;
 for(int i=l+2;i<=s-1;i++)
 map[l+1][i]=t++;
 if(s>=0) fill_map(t,l+1,s-1);
 }
 void print_map1()
 {
 for(int i=1;i<=n;i++)
 {
 for(int j=1;j<n;j++)
 printf("%2d ",map[i][j]);
 printf("%2d\n",map[i][n]);
 }
 }
 void print_map2()
 {
 for(int i=1;i<=n;i++)
 {
 for(int j=1;j<n;j++)
 printf("%d ",map[i][j]);
 printf("%d\n",map[i][n]);
 }
 }
 int main()
 {
 cin>>n;
 fill_map(1,0,n);
 if(n!=10)
 print_map1();
 else
 print_map2();
 return 0;
 }
 ]]></solution>
 <solution language="Python"><![CDATA[# coding=utf-8
 #!/usr/bin/python3
 
 
 def solve(N):
 matrix = [[0 for i in range(0, N)] for i in range(0, N)]
 num = 1
 N_2 = int((N+1)/2)
 for i in range(0, N_2):
 x, y = i, N - i - 1
 matrix[x][y] = num
 while x < y:
 matrix[x][y] = num
 num += 1
 x += 1
 while y > i:
 matrix[x][y] = num
 num += 1
 y -= 1
 while x > i:
 matrix[x][y] = num
 num += 1
 x -= 1
 while y < N - i -1:
 matrix[x][y] = num
 num += 1
 y += 1
 return matrix
 
 
 def print_ans(matrix):
 n = len(matrix)
 for i in range(0, n):
 for j in range(0, n):
 if j == 0 and n <= 3:
 print('{:2d}'.format(matrix[i][j]), sep='', end='')
 elif j == 0:
 print('{:d}'.format(matrix[i][j]), sep='', end='')
 elif n <= 3:
 print(' {:2d}'.format(matrix[i][j]), sep='', end='')
 else:
 print(' {:d}'.format(matrix[i][j]), sep='', end='')
 print('')
 
 
 def main():
 s = input()
 N = int(s)
 print_ans(solve(N))
 
 
 if __name__ == '__main__':
 main()
 
 
 ]]></solution>
 </item>
 </fps>
 
 
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